A) \[C{{H}_{3}}-CH=C{{H}_{2}}\]
B) \[C{{H}_{3}}-C\equiv CH\]
C)
D)
Correct Answer: B
Solution :
[b] \[C{{H}_{3}}-C{{H}_{2}}-CHC{{l}_{2}}\xrightarrow[\Delta ]{NaN{{H}_{2}}}\] \[C{{H}_{3}}-C{{H}_{2}}=CHCl\xrightarrow[\Delta ]{NaN{{H}_{2}}}\underset{Final\text{ }Product}{\mathop{C{{H}_{3}}-C\equiv CH}}\,\]You need to login to perform this action.
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