A) PhLi and \[P{{h}_{3}}P\] respectively
B) \[P{{h}_{3}}P\] and PhLi respectively
C) \[P{{h}_{3}}P\] and \[{{C}_{2}}{{H}_{5}}ONa\] respectively
D) Either [b] or [c]
Correct Answer: D
Solution :
[d] \[C{{H}_{3}}C{{H}_{2}}Br+P{{h}_{3}}P\xrightarrow{{}}C{{H}_{3}}C{{H}_{2}}{{P}^{+}}P{{h}_{3}}B{{r}^{-}}\xrightarrow[{{C}_{2}}{{H}_{5}}ONa]{{{C}_{6}}{{H}_{5}}Li\,or}\]\[C{{H}_{3}}CH=PP{{h}_{3}}\overset{{}}{\longleftrightarrow}C{{H}_{3}}\overset{-}{\mathop{C}}\,H\overset{+}{\mathop{P}}\,P{{h}_{3}}\]You need to login to perform this action.
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