A) propanal
B) butanal
C) n-butyl alcohol
D) n-propyl alcohol
Correct Answer: D
Solution :
[d] \[\underset{(A)}{\mathop{C{{H}_{3}}C{{H}_{2}}I}}\,\xrightarrow[Ether]{Mg}\underset{(B)}{\mathop{C{{H}_{3}}C{{H}_{2}}MgI}}\,\xrightarrow{HCHO}\] \[\underset{(C)}{\mathop{H-\underset{H}{\mathop{\underset{|}{\mathop{\overset{C{{H}_{2}}C{{H}_{3}}}{\mathop{\overset{|}{\mathop{C}}\,}}\,}}\,}}\,-OMgI}}\,\xrightarrow{{{H}_{2}}O}\underset{n-\operatorname{Propyl}\,\,alcohol}{\mathop{\underset{(D)}{\mathop{H-\underset{H}{\mathop{\underset{|}{\mathop{\overset{C{{H}_{2}}C{{H}_{3}}}{\mathop{\overset{|}{\mathop{C}}\,}}\,}}\,}}\,-OH}}\,}}\,\]
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