Which of the following is correct?
A) A on reaction with aq. KOH gives \[HOC{{H}_{2}}C{{H}_{2}}COOK\]
B) B can be resolved into d- and l-forms
C) Both [a] and [b]
D) Neither [a] nor [b]
Correct Answer: C
Solution :
[c] The compound A is \[C{{l}_{3}}C.C{{H}_{2}}.C{{H}_{2}}Cl\xrightarrow{aq.KoH}\] \[{{\left( OH \right)}_{3}}C.C{{H}_{2}}C{{H}_{2}}OH\] \[\xrightarrow{-2{{H}_{2}}O}HOC{{H}_{2}}.C{{H}_{2}}COOK.\] The compounds B is \[C{{l}_{3}}C-\underset{Br}{\mathop{\underset{|}{\overset{*}{\mathop{C}}}\,}}\,H-C{{H}_{2}}Br\] has chiral centre and can be resolved into d- and l- form.
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