NEET Chemistry Hydrocarbons / हाइड्रोकार्बन Question Bank Self Evaluation Test - Hydrocarbons

  • question_answer
    \[HOCl\] reacts on 3-methyl-2-pentene, the main product will be:

    A) \[C{{H}_{3}}-CH=\underset{Cl}{\mathop{\underset{|}{\mathop{C}}\,}}\,-CH-(OH)-C{{H}_{3}}\]

    B) \[C{{H}_{3}}-\overset{OH}{\mathop{\overset{|}{\mathop{C}}\,}}\,H-\overset{C{{H}_{3}}}{\mathop{\overset{|}{\mathop{\underset{Cl}{\mathop{\underset{|}{\mathop{C}}\,}}\,}}\,}}\,-C{{H}_{2}}-C{{H}_{3}}\]

    C) \[C{{H}_{3}}-\overset{Cl}{\mathop{\overset{|}{\mathop{C}}\,}}\,H-\overset{C{{H}_{3}}}{\mathop{\overset{|}{\mathop{\underset{OH}{\mathop{\underset{|}{\mathop{C}}\,}}\,}}\,}}\,-C{{H}_{2}}-C{{H}_{3}}\]

    D) None of these

    Correct Answer: C

    Solution :

    [c] The reaction follows Markownikoff rule \[\underset{3-Methyl-2-pentene}{\mathop{C{{H}_{3}}C{{H}_{2}}-\overset{C{{H}_{3}}}{\mathop{\overset{|}{\mathop{C}}\,}}\,=\overset{H}{\mathop{\overset{|}{\mathop{C}}\,}}\,-C{{H}_{3}}+\overset{\delta -}{\mathop{HO}}\,\overset{\delta +}{\mathop{Cl}}\,}}\,\xrightarrow{{}}C{{H}_{3}}C{{H}_{2}}-\underset{OH}{\mathop{\overset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{\overset{|}{\mathop{C}}\,}}\,}}\,}}\,-\underset{Cl}{\mathop{\overset{H}{\mathop{\underset{|}{\mathop{\overset{|}{\mathop{C}}\,}}\,}}\,}}\,-C{{H}_{3}}\]


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