question_answer

Consider the following sequence of reactions \[C{{H}_{3}}CH=C{{H}_{2}}\xrightarrow[700k]{C{{l}_{2}}}A\xrightarrow[420k,\,12\,atm]{N{{a}_{2}}C{{O}_{3}}}B\] Compound 'B' is

A)           

B)   \[C{{H}_{3}}CH\underset{OH}{\mathop{\underset{|}{\mathop{C}}\,}}\,OONa\]

C) \[HOC{{H}_{2}}-CH=C{{H}_{2}}\]

D) \[C{{H}_{3}}\underset{OH}{\mathop{\underset{|}{\mathop{C}}\,}}\,HOCl\]

Correct Answer: A

Solution :

[a]