A) \[C{{H}_{2}}=C=CH-C{{H}_{3}}\]
B) \[{{H}_{2}}C=\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{C}}\,}}\,-CH=C{{H}_{2}}\]
C) \[C{{H}_{2}}=CH-CH=C{{H}_{2}}\]
D) \[HC\equiv C-CH=C{{H}_{2}}\]
Correct Answer: A
Solution :
[a] \[C{{H}_{2}}=C=CH-C{{H}_{3}}\xrightarrow{{{H}^{+}}}\] \[[C{{H}_{2}}=\overset{+}{\mathop{C}}\,-C{{H}_{2}}-C{{H}_{3}}+C{{H}_{2}}=CH-\overset{+}{\mathop{C}}\,H-C{{H}_{3}}]\]You need to login to perform this action.
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