A) mixture of secondary and tertiary alcohols
B) mixture of primary and secondary alcohols
C) secondary or tertiary alcohol
D) primary alcohol
Correct Answer: C
Solution :
[c] \[C{{H}_{3}}-CH=C{{H}_{2}}+{{H}_{2}}O\xrightarrow{{{H}_{2}}S{{O}_{4}}}\underset{2{}^\circ \,alcohol}{\mathop{C{{H}_{3}}-\underset{OH}{\mathop{\underset{|}{\mathop{CH}}\,}}\,-C{{H}_{3}}}}\,\]\[C{{H}_{3}}-\overset{C{{H}_{3}}}{\mathop{\overset{|}{\mathop{C}}\,}}\,=C{{H}_{2}}+{{H}_{2}}O\xrightarrow{{{H}_{2}}S{{O}_{4}}}\underset{3{}^\circ \,alcohol}{\mathop{C{{H}_{3}}-\underset{OH}{\overset{C{{H}_{3}}}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}}\,-C{{H}_{3}}}}\,\]Addition follows Markovnikov's rule.
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