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NEET Chemistry Hydrocarbons / हाइड्रोकार्बन Question Bank Self Evaluation Test - Hydrocarbons

  • question_answer
    An unknown compound A has a molecular formula \[{{C}_{2}}{{H}_{6}}\], when A is treated with an excess of\[B{{r}_{2}}\], a new substance B with formula \[{{C}_{4}}{{H}_{6}}B{{r}_{2}}\]is formed. A forms a white precipitate with ammonical silver nitrate solution. A may be

    A) Butyne-1          

    B) Butyne-2

    C) Butene-1           

    D) Butene-2

    Correct Answer: A

    Solution :

    [a] Conversion of \[{{C}_{4}}{{H}_{6}}\] to \[{{C}_{4}}{{H}_{6}}B{{r}_{2}}\] indicates that the compound is either butyne-1 or butyne-2. However, white precipitate with ammonical silver nitrate solution indicates that it is a terminal alkyne, i.e. butyne-1 and not butyne-2


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