A) 0 and -1
B) -1 and -2
C) -2 and 0
D) -2 and +1
Correct Answer: B
Solution :
[b] \[Ba{{O}_{2}}+{{H}_{2}}S{{O}_{4}}\to BaS{{O}_{4}}+{{H}_{2}}{{O}_{2}}\] oxygen has common O.S. as \[-2\] and in peroxides as -1 .
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