A) 25.5 g
B) 3.0 g
C) 8.0 g
D) 2.5 g
Correct Answer: A
Solution :
[a] Molecular weight of \[{{H}_{2}}{{O}_{2}}=34\] Equivalent weight of \[{{H}_{2}}{{O}_{2}}=17\] \[\therefore \] 1 L of 1 \[N\,{{H}_{2}}{{O}_{2}}\] has =17g of \[{{H}_{2}}O\] \[\therefore \] 1 L of \[1.5N\,{{H}_{2}}{{\text{O}}_{2}}\] has \[=1.5\times 17=25.5g\,of\,{{H}_{2}}{{O}_{2}}\]You need to login to perform this action.
You will be redirected in
3 sec