A) x
B) 1
C) \[\cos x\]
D) \[sinx\]
Correct Answer: D
Solution :
[d] Since \[\int{f{{[x]}^{n}}f'(x)dx=\frac{{{[f(x)]}^{n+1}}}{n+1}+c}\] \[\therefore \int{f(x)\cos \,\,x\,\,dx=\frac{{{f}^{2}}(x)}{2}+c}\] \[\Rightarrow f'(x)=\cos \,\,x\Rightarrow f(x)=\sin \,\,x\]You need to login to perform this action.
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