A) \[\frac{-19}{6}\]
B) \[\frac{19}{6}\]
C) \[\frac{3}{2}\]
D) \[-\frac{3}{2}\]
Correct Answer: A
Solution :
[a] Value of the integral \[\int\limits_{2}^{9}{f(x)dx}\] \[=\int\limits_{-3}^{9}{f(x)dx-\int\limits_{-3}^{2}{f(x)dx}}\] ? (i) Given, \[\int\limits_{-3}^{9}{f(x)dx=\frac{-5}{6}}\] and \[\int\limits_{-3}^{2}{f(x)dx=\frac{7}{3}}\] Putting these values in equation (i) \[\int\limits_{2}^{9}{f(x)dx=\frac{-5}{6}-\frac{7}{3}=-\frac{19}{6}}\]
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