A) \[\left\{ 1,2 \right\}\]
B) \[\left\{ -1,2 \right\}\]
C) \[\left\{ -1,1,0 \right\}\]
D) \[\left\{ 1,1/2,0 \right\}\]
Correct Answer: C
Solution :
[c] \[{{\sin }^{-1}}x=2{{\tan }^{-1}}x\] \[\Rightarrow {{\sin }^{-1}}x={{\sin }^{-1}}\{2x/(1+{{x}^{2}})\}\] \[\Rightarrow 2x/(1+{{x}^{2}})=x\] \[\Rightarrow x(x+1)(x-1)=0\Rightarrow x=\{-1,1,0\}\]
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