A) \[\frac{\pi }{4}\]
B) \[\frac{3\pi }{4}\]
C) \[\frac{\pi }{6}\]
D) \[\frac{\pi }{3}\]
Correct Answer: B
Solution :
[b] The sum of the two given angles is \[{{\cot }^{-1}}(2)+co{{t}^{-1}}(3)=ta{{n}^{-1}}\left( \frac{1}{2} \right)+{{\tan }^{-1}}\left( \frac{1}{3} \right)\] \[={{\tan }^{-1}}(1)=\frac{\pi }{4}\] So, the third angle is \[\pi -\frac{\pi }{4}=\frac{3\pi }{4}\]
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