A) \[121/96\]
B) \[211/921\]
C) \[146/121\]
D) \[267/121\]
Correct Answer: C
Solution :
[c] Let \[{{\sec }^{2}}\left( {{\tan }^{-1}}\left( \frac{5}{11} \right) \right)\] \[=1+{{\tan }^{2}}\left( {{\tan }^{-1}}\left( \frac{5}{11} \right) \right)\left( \because {{\sec }^{2}}\theta -{{\tan }^{2}}\theta =1 \right)\] \[=1+{{\left[ \tan \left( {{\tan }^{-1}}\left( \frac{5}{11} \right) \right) \right]}^{2}}=1+{{\left( \frac{5}{11} \right)}^{2}}\] \[=1+\frac{25}{121}=\frac{146}{121}\]
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