A) \[[-1,1]\]
B) \[[0,1]\]
C) \[[-1,0]\]
D) \[\left[ -1/\sqrt{2},1/\sqrt{2} \right]\]
Correct Answer: D
Solution :
[d] \[{{\sin }^{-1}}\{2x(1-{{x}^{2}})\}=2si{{n}^{-1}}x\] is true \[\forall x\in \left[ -\frac{1}{\sqrt{2}},\frac{1}{\sqrt{2}} \right]\]
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