A) \[\sqrt{2}\] times
B) 2 times
C) unchanged
D) half
Correct Answer: B
Solution :
[b] Average K.E.\[=\frac{1}{2}m{{c}^{2}}=\frac{3}{2}kT\]3 \[\therefore \frac{{{\left( \text{Av}\text{. K}\text{.E}\text{.} \right)}_{600K}}}{{{\left( \text{Av}\text{. K}\text{.E}\text{.} \right)}_{400K}}}=\frac{600}{300}=2\] \[\therefore \]At 600K it will be 2 times than that at 300K.
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