A) 80 K
B) -73 K
C) 3 K
D) 20 K
Correct Answer: D
Solution :
[d] \[{{v}_{rms}}=\sqrt{\frac{8RT}{\pi M}}\] For \[{{v}_{rms}}\] to be equal \[\frac{{{T}_{{{H}_{2}}}}}{{{M}_{{{H}_{2}}}}}=\frac{T{{O}_{2}}}{M{{O}_{2}}}\] Here \[{{M}_{{{H}_{2}}}}=2;\,\,\,\,\,\,{{M}_{{{O}_{2}}}}=32\,\,\,\,;\] \[{{T}_{{{O}_{2}}}}=47+273=320K\] \[\therefore \frac{{{T}_{{{H}_{2}}}}}{2}=\frac{320}{32}\Rightarrow {{T}_{{{H}_{2}}}}=20K\]
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