A) P
B) 2P
C) P/2
D) 4P
Correct Answer: B
Solution :
[b] \[{{v}_{rms}}=\sqrt{\frac{3P}{\rho }}=\sqrt{\frac{3PV}{m}}\Rightarrow P=\frac{m\,{{({{v}_{rms}})}^{2}}}{3V}\] If P' be the final pressure then \[\frac{P'}{P}=\left[ \frac{\frac{\frac{m}{2}{{\left( 2{{v}_{rms}} \right)}^{2}}}{3V}}{\frac{m{{\left( {{v}_{rms}} \right)}^{2}}}{3V}} \right]=2\Rightarrow P'=2P.\]
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