A) 2
B) 1
C) 1/3
D) 2/3
Correct Answer: D
Solution :
[d] Mean kinetic energy of the two types of molecules should be equal. The mean square velocity of A type molecules =\[{{\omega }^{2}}+{{\omega }^{2}}=3{{\omega }^{2}}\] Therefore, \[\frac{1}{2}m\left( 3{{\omega }^{2}} \right)=\frac{1}{2}\left( 2m \right){{v}^{2}}\] This gives \[{{\omega }^{2}}/{{v}^{2}}=2/3\]You need to login to perform this action.
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