A) \[2\times {{10}^{27}}\]
B) \[~2\times {{10}^{20}}\]
C) \[2\times {{10}^{10}}\]
D) \[~2\times {{10}^{24}}\]
Correct Answer: A
Solution :
[a] Number of collisions can be calculated as \[2(m{{v}_{rms}})=PA\] \[\therefore \,\,\,\,n=\left[ \frac{PA}{2m{{v}_{rms}}} \right]\,\,;\,\,{{v}_{rms}}=\sqrt{\frac{3kT}{m}}\]
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