A) \[1500{{m}^{3}}~\]
B) \[~1700{{m}^{3}}\]
C) \[1900{{m}^{3}}\]
D) \[~2700{{m}^{3}}\]
Correct Answer: D
Solution :
[d] \[\frac{{{P}_{1}}{{V}_{1}}}{{{T}_{1}}}=\frac{{{P}_{2}}{{V}_{2}}}{{{T}_{2}}}\] \[\therefore {{V}_{2}}=\frac{{{P}_{1}}{{V}_{1}}}{{{T}_{2}}}\times \frac{{{T}_{2}}}{{{P}_{2}}}=\frac{4\times 1500\times 270}{300\times 2}=2700{{m}^{3}}\]
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