A) x
B) \[\frac{383}{283}x\]
C) \[\frac{10}{110}x\]
D) \[\frac{283}{383}x\]
Correct Answer: D
Solution :
[d] Let the mass of the gas be m. At a fixed temperature and pressure, volume is fixed. Density of the gas, \[\rho =\frac{m}{V}\] Now \[\frac{\rho }{P}=\frac{m}{PV}=\frac{m}{nRT}\] \[\Rightarrow \frac{m}{nRT}=x\left( \text{By question} \right)\] \[\Rightarrow xT=\text{constant}\Rightarrow {{x}_{1}}{{T}_{1}}={{x}_{2}}{{T}_{2}}\] \[\Rightarrow {{x}_{2}}\Rightarrow \frac{{{x}_{1}}{{T}_{1}}}{{{T}_{2}}}=\frac{283}{383}\times \left[ \begin{align} & \therefore \\ & {{T}_{1}}=283K \\ & {{T}_{2}}=383K \\ \end{align} \right]\]
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