JEE Main & Advanced Physics Kinetic Theory of Gases Question Bank Self Evaluation Test - Kinetic Theory

  • question_answer
    A perfect gas at \[27{}^\circ C\] is heated at constant pressure so as to double its volume. The final temperature of the gas will be, close to

    A) (a)\[327{}^\circ C\]      

    B)        \[200{}^\circ C\]

    C) \[54{}^\circ C\]

    D)        \[300{}^\circ C\]

    Correct Answer: A

    Solution :

    [a] Given, \[{{V}_{1}}=V,{{V}_{2}}=2V\] \[{{T}_{1}}=27{}^\circ +273=300K\text{ so, }{{T}_{2}}=?\] From charle's law \[\frac{{{V}_{1}}}{{{T}_{1}}}=\frac{{{V}_{2}}}{{{T}_{2}}}\text{ or, }\frac{V}{300}=\frac{2V}{{{T}_{2}}}\]                            (\[\therefore \]Pressure is constant) \[\therefore ~\,\,\,\,\,{{T}_{2}}=600K=600-273=327{}^\circ C\]


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