A) \[{{r}^{3}}\]
B) \[{{r}^{2}}\]
C) \[r\]
D) \[\sqrt{r}\]
Correct Answer: B
Solution :
[b] Mean free path \[{{\lambda }_{m}}=\frac{1}{\sqrt{2}\pi {{d}^{2}}n}\] Where d = diameter of molecule and \[d=2r\] \[\therefore {{\lambda }_{m}}\propto \frac{1}{{{r}^{2}}}\]
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