A) \[\frac{nkT}{N}\]
B) \[\frac{nkT}{2N}\]
C) \[\frac{nkT}{2}\]
D) \[\frac{3kT}{2}\]
Correct Answer: C
Solution :
[c] According to law of equipartition of energy, the energy per degree of freedom is \[\frac{1}{2}kT.\] For a polyatomic gas with n degrees of freedom, the mean energy per molecule \[=\frac{1}{2}nkT\]
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