A) 30 K
B) 18 K
C) 50 K
D) 42 K
Correct Answer: D
Solution :
[d] A is free to move, therefore heat will be supplied at constant pressure \[\therefore \Delta {{Q}_{A}}=n{{C}_{p}}\Delta {{T}_{A}}\] ?.(i) B is held fixed, therefore heat will be supplied at constant volume. \[\therefore \Delta {{Q}_{B}}=n{{C}_{v}}\Delta {{T}_{B}}\] ?(ii) But \[\Delta {{Q}_{A}}=\Delta {{Q}_{B}}\] (given) \[\therefore n{{C}_{p}}\Delta {{T}_{A}}=n{{C}_{v}}\Delta {{T}_{B}}\] \[\therefore \Delta {{T}_{B}}=\left( \frac{{{C}_{p}}}{{{C}_{v}}} \right)\Delta {{T}_{A}}\] \[=\gamma \left( \Delta {{T}_{A}} \right)\text{ }\left[ \gamma =1.4\left( \text{diaatomic} \right) \right]\] \[=\left( 1.4 \right)\left( 30K \right)\] \[\therefore \,\,\,\,\,\,\,\,\,\,\,\,\,\,\Delta {{T}_{B}}=42K\]
You need to login to perform this action.
You will be redirected in
3 sec
