A) 1.979kcal/k mol K
B) 2.378 kcal/k mol K
C) 4.569 kcal/k mol K
D) 3.028 kcal/k mol K
Correct Answer: A
Solution :
[a] \[V=22.4litre=22.4\times {{10}^{-3}}{{m}^{3}},J=4500J/kcal\] By ideal gas equation for one mole of a gas, \[R=\frac{PV}{T}=\frac{1.013\times {{10}^{5}}\times 22.4\times {{10}^{-3}}}{273}\] \[{{C}_{p}}-{{C}_{v}}=\frac{R}{J}=\frac{1.013\times {{10}^{5}}\times 22.4}{273\times 4200}=1.979\] kcal/kmol K
You need to login to perform this action.
You will be redirected in
3 sec
