A) \[{{C}_{p}}=1.33\times {{10}^{4}},{{C}_{V}}=2.66\times {{10}^{4}}\]
B) \[{{C}_{p}}=13.3\times {{10}^{4}},{{C}_{V}}=8.33\times {{10}^{4}}\]
C) \[{{C}_{p}}=1.33\times {{10}^{4}},{{C}_{V}}=8.33\times {{10}^{3}}\]
D) \[{{C}_{p}}=2.6\times {{10}^{4}},{{C}_{V}}=8.33\times {{10}^{4}}\]
Correct Answer: C
Solution :
[c] Given \[{{C}_{p}}-{{C}_{v}}=5000J/mole{}^\circ \text{C}\] ?.(i) \[\frac{{{C}_{p}}}{{{C}_{v}}}=1.6\] ?(ii) From Equation (i) & (ii), \[\frac{{{C}_{P}}}{{{C}_{V}}}-\frac{{{C}_{V}}}{{{C}_{V}}}=\frac{5000}{{{C}_{V}}}\Rightarrow 1.6-1=\frac{5000}{{{C}_{V}}}\] \[\Rightarrow {{C}_{V}}=\frac{5000}{0.6}=8.33\times {{10}^{3}}\] \[\text{Hence }{{C}_{p}}=1.6,\text{ }{{C}_{V}}=1.6\times 8.33\times {{10}^{3}}\] \[=1.33\times {{10}^{4}}\]
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