JEE Main & Advanced Physics Kinetic Theory of Gases Question Bank Self Evaluation Test - Kinetic Theory

  • question_answer
    The K.E. of one mole of an ideal gas is E=(3/2) RT. Then \[{{C}_{p}}\]will be

    A) 0.5 R

    B) 0.1 R

    C) 1.5 R

    D) 2.5 R

    Correct Answer: D

    Solution :

    [d] \[{{C}_{v}}=dE/dT=\frac{3}{2}R\] \[{{C}_{p}}=\frac{3}{2}R+R=\frac{5}{2}R=2.5R\]


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