| A mass of 1 kg is suspended by a thread. It is |
| (i) lifted up with an acceleration \[4.9\text{ }m/{{s}^{2}}\], |
| (ii) Lowered with an acceleration\[4.9\text{ }m/{{s}^{2}}\]. |
| The ratio of the tensions is |
A) \[3\text{ }:\text{ }1\]
B) \[1\text{ }:\text{ }2\]
C) \[1\text{ }:\text{ }3\]
D) \[2\text{ }:\text{ }1\]
Correct Answer: A
Solution :
[a] In case (i) we have \[{{T}_{1}}-\left( 1\times g \right)=1\times 4.9\] \[\Rightarrow {{T}_{1}}=9.8+4.9=14.7\text{ N}\] In case (ii) \[,1\times g-{{T}_{2}}=1\times 4.9\] \[\Rightarrow {{T}_{2}}=9.8-4.9=4.9\text{ N }\therefore \frac{{{T}_{1}}}{{{T}_{2}}}=\frac{14.7}{4.9}=\frac{3}{1}\]
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