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JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Self Evaluation Test - Laws of Motion

  • question_answer
    An object of mass 10 kg moves at a constant speed of\[10\text{ }m{{s}^{-1}}\]. A constant force that acts for 4 sec on the object gives it a speed of \[2\text{ }m{{s}^{-1}}\] in opposite direction. The force acting on the object is

    A) -3N

    B) -30 N

    C) 3N

    D) 30 N

    Correct Answer: B

    Solution :

    [b] \[Here\text{ }u=10m{{s}^{-1}},v=-2m{{s}^{-1}},\text{ }t=4s,\text{ }a=?\] Using \[a=\frac{v-u}{t}=\frac{-2-10}{4}=-3m/{{s}^{2}}\] \[\therefore \text{Force, }F\text{=}ma=10\times \left( -3 \right)=-30N\]


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