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JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Self Evaluation Test - Laws of Motion

  • question_answer
    A player stops a football weighting 0.5 kg which comes flying towards him with a velocity of 10m/ s. If the impact lasts for 1/50th sec. and the ball bounces back with a velocity of 15 m/s, then the average force involved is

    A) 250 N

    B) 1250 N

    C) 500 N

    D) 625 N

    Correct Answer: D

    Solution :

    [d] \[\text{Here }m=0.5kg;\text{ }u=-10m/s;\] \[t\text{ }=\text{ }1/50s;v=+15m{{s}^{-1}}\] \[\text{Force}=m(v-u)/t=0.5(10+15)\times 50\text{ }=625N\]


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