JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Self Evaluation Test - Laws of Motion

  • question_answer
    The force required to stop a car of mass 800 kg, moving at a speed of \[20\text{ }m{{s}^{-1}}\] over a distance of 25m in 2.5 sec is

    A) 1200N

    B) 6400 N

    C) 1600N

    D) 1800N

    Correct Answer: B

    Solution :

    [b] As we know, \[|a|=\left| \frac{{{v}^{2}}-{{u}^{2}}}{2S} \right|=\frac{400}{50}=8\text{ m/}{{\text{s}}^{2}}.\] So force required \[=F=ma\] \[=800\times 8=6400\text{ }N\]


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