2. Questions Bank
  3. JEE Main & Advanced
  4. Physics
  5. NLM, Friction, Circular Motion

JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Self Evaluation Test - Laws of Motion

  • question_answer
    A stone is dropped from a height h. It hits the ground with a certain momentum P. If the same stone is dropped from a height 100% more than the previous height, the momentum when it hits the ground will change by:

    A) 68%

    B) 41%

    C) 200%

    D) 100%

    Correct Answer: B

    Solution :

    [b] Momentum \[P=mv=m\sqrt{2gh}\] \[\left( \therefore {{v}^{2}}={{u}^{2}}+2gh;\text{ Here }u=0 \right)\] When stone hits the ground momentum \[P=m\sqrt{2gh}\] When same stone dropped from 2h (100% of initial) then momentum \[{P}'=m\sqrt{2g(2h)}=\sqrt{2}P\] Which is changed by 41 % of initial.


You need to login to perform this action.
You will be redirected in 3 sec spinner