JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Self Evaluation Test - Laws of Motion

  • question_answer
    The force 'F' acting on a particle of mass 'm' is indicated by the force-time graph shown below. The change in momentum of the particle over the time interval from zero to 8 s is:

    A) 24 Ns

    B) 20 Ns

    C) 12 Ns

    D) 6 Ns

    Correct Answer: C

    Solution :

    [c] Change in momentum, \[\Delta p=\int_{{}}^{{}}{Fdt}\] \[=\text{Area of F-t graph }\] \[\text{= ar of }\Delta -\text{ ar of }\text{ }+\text{ ar of }\] \[=\frac{1}{2}\times 2\times 6-3\times 2+4\times 3=12\text{ N-s}\]


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