A) \[T+\frac{m{{v}^{2}}}{l}\]
B) \[T-\frac{m{{v}^{2}}}{l}\]
C) Zero
D) T
Correct Answer: D
Solution :
[d] Net force on particle in uniform circular motion is centripetal force \[\left( \frac{m{{v}^{2}}}{l} \right)\] which is provided by tension in string so the net force will be equal to tension i.e., T.
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