JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Self Evaluation Test - Laws of Motion

  • question_answer
    A monkey of mass 20 kg is holding a vertical rope. The rope will not break when a mass of 25 g is suspended from it but will break if the mass exceeds 25 kg. What is the maximum acceleration with which the monkey can climb up along the rope? \[\left( g=10\text{ }m/{{s}^{2}} \right)\]

    A) \[2.5\text{ }m/s\]  

    B) \[5\text{ }m/{{s}^{2}}\]

    C) \[\text{10 }m/{{s}^{2}}\]    

    D) \[\text{25 }m/{{s}^{2}}\]

    Correct Answer: A

    Solution :

    [a] \[T=\]Tension caused in string by monkey \[=m\left( g+a \right)\] \[\therefore T\le 25\times 10\Rightarrow 20\left( 10+a \right)\le 250\] or, \[10+a12.5\Rightarrow a\le 2.5\]


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