A) 0
B) \[30{}^\circ \]
C) \[60{}^\circ \]
D) \[45{}^\circ \]
Correct Answer: B
Solution :
[b] \[{{T}_{2}}\sin \theta +{{T}_{1}}\sin 60{}^\circ =W\] \[{{T}_{1}}\cos 60{}^\circ ={{T}_{2}}\cos \theta \] \[{{T}_{2}}\sin \theta +{{T}_{2}}\cos \theta .\tan 60{}^\circ =W\] \[{{T}_{2}}(\sin \theta +\sqrt{3}\cos \theta )=W\] \[2{{T}_{2}}(\sin 30{}^\circ \sin \theta +\cos 30{}^\circ \cos \theta )=W\] \[\cos \left( 30{}^\circ -\theta \right)\text{ is maximum}\] \[\text{If }30{}^\circ -\theta =0;\text{ }\theta =\text{30}{}^\circ \]
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