A)
B)
C)
D)
Correct Answer: B
Solution :
[b] \[\text{Let }{{\text{m}}_{1}}\text{+}{{\text{m}}_{2}}\text{+}{{\text{m}}_{3}}\text{=constant an}d\] \[{{m}_{1}}=x\Rightarrow {{m}_{2}}=m-x\] \[a=\frac{x-\left( m-x \right)}{m}g\]\[T=\frac{2x\left( m-x \right)}{m}g\Rightarrow T=\frac{m}{2g}\left( {{g}^{2}}-{{a}^{2}} \right)\]
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