A) \[\mu =\frac{2}{\tan \theta }\]
B) \[\mu =2\tan \theta \]
C) \[\mu =2\tan \theta \]
D) \[\mu =\frac{1}{\tan \theta }\]
Correct Answer: B
Solution :
[b] For upper half of inclined plane \[{{v}^{2}}={{u}^{2}}+2aS/2=2\left( g\sin \theta \right)S/2=gS\sin \theta \] For lower half of inclined plane \[0={{u}^{2}}+2g\left( \sin \theta -\mu \cos \theta \right)S/2\] \[\Rightarrow -gS\sin \theta =gS\left( \sin \theta -\mu \cos \theta \right)\] \[\Rightarrow 2\sin \theta =\mu \cos \theta \] \[\Rightarrow \mu =\frac{2\sin \theta }{\cos \theta }=2\tan \theta \]You need to login to perform this action.
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