JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Self Evaluation Test - Laws of Motion

  • question_answer
    A smooth ring P of mass m can slide on a fixed horizontal rod. A string tied to the ring passes over a fixed pulley and carries a block Q of mass (mil) as shown in the figure. At an instant, the string between the ring and the pulley makes an angle \[60{}^\circ \]with the rod. The initial acceleration of the ring is

    A) \[\frac{2g}{3}\]  

    B) \[\frac{2g}{6}\]

    C) \[\frac{2g}{9}\]  

    D) \[\frac{g}{3}\]

    Correct Answer: C

    Solution :

    [c] \[\frac{m}{2}g-T=\frac{m}{2}a\]   ?.(i) \[T\cos 60{}^\circ =\frac{ma}{\cos 60{}^\circ }\]   ?(ii) Solving (i) and (ii), Acceleration of ring \[=\frac{2g}{9}\]


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