JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Self Evaluation Test - Laws of Motion

  • question_answer
    In the figure acceleration of bodies A, B and C are shown with directions. Values b and c are w.r.t. ground whereas a is acceleration of block A w.r.t. sedge C. Acceleration of block A w.r.t. ground is

    A) \[\sqrt{{{\left( b+c \right)}^{2}}+{{a}^{2}}}\]

    B)        \[c-\left( a+b \right)\cos \theta \]

    C) \[\sqrt{{{\left( b+c \right)}^{2}}+{{c}^{2}}-2\left( b+c \right).c.\cos \theta }\]    

    D) \[\sqrt{{{\left( b+c \right)}^{2}}+{{c}^{2}}+2\left( b+c \right).c.\cos \theta }\]

    Correct Answer: C

    Solution :

    [c] \[a=b+c\] Net acceleration of A \[=\sqrt{{{a}^{2}}+{{c}^{2}}+2ac\cos \left( \pi -\theta  \right)}\] \[=\sqrt{{{\left( b+c \right)}^{2}}+{{c}^{2}}-2\left( b+c \right)c.\cos \theta }\]


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