A) \[\frac{2mg}{3A}\]
B) \[\frac{4mg}{3A}\]
C) \[\frac{mg}{A}\]
D) \[\frac{3mg}{4A}\]
Correct Answer: B
Solution :
[b] Tension in the wire, \[T=\left( \frac{2mM}{m+M} \right)g\] \[=\frac{\text{Force/Tension}}{\text{Area}}=\frac{2mM}{A\left( m+M \right)}g\] \[=\frac{2\left( m\times 2m \right)g}{A\left( m+2m \right)}=\frac{4{{m}^{2}}}{3mA}g=\frac{4mg}{3A}\] \[\left( M=2m\text{ given} \right)\]
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