A) \[4:3~\]
B) \[1:4\]
C) \[1:2\]
D) \[1:3\]
Correct Answer: A
Solution :
[a] \[{{T}_{1}}=m{{\omega }^{2}}(3\,\ell )\] and\[{{T}_{2}}-{{T}_{1}}=m{{\omega }^{2}}\ell \] or \[{{T}_{2}}={{T}_{1}}+m{{\omega }^{2}}\ell =m{{\omega }^{2}}(3\ell )+m{{\omega }^{2}}\ell \] \[=4m{{\omega }^{2}}\ell \] \[\therefore \frac{{{T}_{2}}}{{{T}_{1}}}=\frac{4}{3}\]You need to login to perform this action.
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