JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Self Evaluation Test - Laws of Motion

  • question_answer
    Two smooth cylindrical bars weighing W each lie next to each other in contact. A similar third bar is placed over the two bars as shown in figure. Neglecting friction, the minimum horizontal force on each lower bar necessary to keep them together is

    A) \[\frac{W}{2}\]  

    B) \[W\]

    C) \[\frac{W}{\sqrt{3}}\]  

    D) \[\frac{W}{2\sqrt{3}}\]

    Correct Answer: D

    Solution :

    [d] \[2N\cos 30{}^\circ =W.\] \[N=\frac{W}{\sqrt{3}}\] \[\text{and }N\sin 30{}^\circ =F\] \[\text{or }\frac{W}{\sqrt{3}}\times \frac{1}{2}=F,\text{ or F=}\frac{W}{2\sqrt{3}}.\]


You need to login to perform this action.
You will be redirected in 3 sec spinner