A) 1.2 m
B) 0.6 m
C) zero
D) 0.4 m
Correct Answer: D
Solution :
[d] Frictional force on the box \[f=\text{ }\mu mg\] \[\therefore \text{ Acceleration in the box a = }\mu \text{g =5m}{{\text{s}}^{-2}}\] \[{{v}^{2}}={{u}^{2}}+2aS\Rightarrow 0={{2}^{2}}+2\times \left( 5 \right)s\Rightarrow s=-\frac{2}{5}\] \[\text{w}\text{.r}\text{.t}\text{. belt }\Rightarrow \text{ distance = 0}\text{.4m}\]
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