A) 1
B) 2
C) 3
D) 4
Correct Answer: C
Solution :
[c] For the upward motion of the body \[\operatorname{mg} sin \theta + {{f}_{1}} = {{F}_{1}}\] or, \[{{F}_{1}} = mg sin \theta +\mu \,\,mg cos \theta \] For the downward motion of the body, \[\operatorname{mg}\,\,sin\,\,\theta -{{f}_{2}}={{F}_{2}}\] \[or\text{ }{{F}_{2}}=\text{ }mg\text{ }sin\text{ }\theta \text{ }-\text{ }\mu \,\,mg\text{ }cos\text{ }\theta \] \[\therefore \frac{{{F}_{1}}}{{{F}_{2}}}=\frac{sin\theta +\mu \,\,cos\,\,\theta }{sin\theta -\mu \,\,cos\,\,\theta }\] \[\Rightarrow \frac{\tan \theta + \mu }{\tan \theta - \mu }= \frac{2\mu +\mu }{2\mu -\mu }=\frac{3\mu }{\mu }=3\]You need to login to perform this action.
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