A) 30 N
B) 25 N
C) 27 N
D) 48 N
Correct Answer: C
Solution :
[c] Minimum force on A =frictional force between the surfaces = 12 N Therefore maximum acceleration \[{{a}_{\max }}=\frac{12\,N}{4kg}=3\,m/{{s}^{2}}\] Hence maximum force, \[{{\operatorname{F}}_{max}}=total\,\,mass\times {{a}_{max}}=9\times 3=27\,\,N\]You need to login to perform this action.
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